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Here's Le Monde puzzle #824:
Show that, for any integer y, (√3−1)2y+(√3+1)2y is an integer multiple of a power of two.
Solution:
Consider f(n)=(−1+√3)n+(−1−√3)n and observe that the two bases are the roots of the quadratic x2+2x−2, hence f(n) obeys the recursion xn+2=−2xn+1+2xn with x0=2 and x1=−2. It follows that f(n) is always an even integer.
Show that, for any integer y, (√3−1)2y+(√3+1)2y is an integer multiple of a power of two.
Solution:
Consider f(n)=(−1+√3)n+(−1−√3)n and observe that the two bases are the roots of the quadratic x2+2x−2, hence f(n) obeys the recursion xn+2=−2xn+1+2xn with x0=2 and x1=−2. It follows that f(n) is always an even integer.
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